Nilai \( \displaystyle \lim_{x \to -4} \ \frac{x^2+7x+12}{2x+8} = \cdots \)
- \( -1 \)
- \( -\frac{1}{2} \)
- \( \frac{7}{8} \)
- \( \frac{3}{2} \)
- \( \frac{7}{2} \)
(UN SMA IPS 2014)
Pembahasan:
\begin{aligned} \lim_{x \to -4} \ \frac{x^2+7x+12}{2x+8} &= \lim_{x \to -4} \ \frac{(x+3)(x+4)}{2(x+4)} \\[8pt] &= \lim_{x \to -4} \ \frac{x+3}{2} \\[8pt] &= \frac{-4+3}{2} = -\frac{1}{2} \end{aligned}
Jawaban B.